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在keras自定义层中使用广播进行元素乘法

[英]element-wise multiplication with broadcasting in keras custom layer

I am creating a custom layer with weights that need to be multiplied by element-wise before activation. 我正在创建一个自定义图层,其权重需要在激活之前按元素乘以。 I can get it to work when the output and input is the same shape. 当输出和输入是相同的形状时,我可以使它工作。 The problem occurs when I have a first order array as input with a second order array as output. 当我将第一个数组作为输入并将第二个数组作为输出时,会出现问题。 tensorflow.multiply supports broadcasting, but when I try to use it in Layer.call(x, self.kernel) to multiply x by the self.kernel Variable it complains that they are different shapes saying: tensorflow.multiply支持广播,但是当我尝试在Layer.call(x,self.kernel)中使用它来将x乘以self.kernel变量时,它会抱怨它们是不同的形状:

ValueError: Dimensions must be equal, but are 4 and 3 for 'my_layer_1/Mul' (op: 'Mul') with input shapes: [?,4], [4,3].

here is my code: 这是我的代码:

from keras import backend as K
from keras.engine.topology import Layer
import tensorflow as tf
from keras.models import Sequential
import numpy as np

class MyLayer(Layer):

    def __init__(self, output_dims, **kwargs):
        self.output_dims = output_dims

        super(MyLayer, self).__init__(**kwargs)

    def build(self, input_shape):
        # Create a trainable weight variable for this layer.
        self.kernel = self.add_weight(name='kernel',
                                      shape=self.output_dims,
                                      initializer='ones',
                                      trainable=True)


        super(MyLayer, self).build(input_shape)  # Be sure to call this somewhere!

    def call(self, x):
        #multiply wont work here?
        return K.tf.multiply(x, self.kernel)

    def compute_output_shape(self, input_shape):
        return (self.output_dims)

mInput = np.array([[1,2,3,4]])
inShape = (4,)
net = Sequential()
outShape = (4,3)
l1 = MyLayer(outShape, input_shape= inShape)
net.add(l1)
net.compile(loss='mean_absolute_error', optimizer='adam', metrics=['accuracy'])
p = net.predict(x=mInput, batch_size=1)
print(p)

Edit: Given input shape (4,) and output shape (4,3) the weight matrix should be the same shape as the output and initialized with ones. 编辑:给定输入形状(4,)和输出形状(4,3),权重矩阵应与输出形状相同,并用1初始化。 So in the above code the input is [1,2,3,4], the weight matrix should be [[1,1,1,1],[1,1,1,1],[1,1,1,1]] and the output should look like [[1,2,3,4],[1,2,3,4],[1,2,3,4]] 所以在上面的代码中输入是[1,2,3,4],权重矩阵应该是[[1,1,1,1],[1,1,1,1],[1,1,1] ,1]],输出应该像[[1,2,3,4],[1,2,3,4],[1,2,3,4]]

Before multiplying, you need to repeat the elements to increase the shape. 在乘法之前,您需要重复元素以增加形状。 You can use K.repeat_elements for that. 您可以使用K.repeat_elements ( import keras.backend as K ) import keras.backend as K

class MyLayer(Layer):

    #there are some difficulties for different types of shapes   
    #let's use a 'repeat_count' instead, increasing only one dimension
    def __init__(self, repeat_count,**kwargs):
        self.repeat_count = repeat_count
        super(MyLayer, self).__init__(**kwargs)

    def build(self, input_shape):

        #first, let's get the output_shape
        output_shape = self.compute_output_shape(input_shape)
        weight_shape = (1,) + output_shape[1:] #replace the batch size by 1


        self.kernel = self.add_weight(name='kernel',
                                      shape=weight_shape,
                                      initializer='ones',
                                      trainable=True)


        super(MyLayer, self).build(input_shape)  # Be sure to call this somewhere!

    #here, we need to repeat the elements before multiplying
    def call(self, x):

        if self.repeat_count > 1:

             #we add the extra dimension:
             x = K.expand_dims(x, axis=1)

             #we replicate the elements
             x = K.repeat_elements(x, rep=self.repeat_count, axis=1)


        #multiply
        return x * self.kernel


    #make sure we comput the ouptut shape according to what we did in "call"
    def compute_output_shape(self, input_shape):

        if self.repeat_count > 1:
            return (input_shape[0],self.repeat_count) + input_shape[1:]
        else:
            return input_shape

here is another solution that is based on the answer by Daniel Möller, but uses tf.multiply like the original code. 这是另一个基于DanielMöller答案的解决方案,但是像原始代码一样使用tf.multiply。

class MyLayer(Layer):

    def __init__(self, output_dim, **kwargs):
        self.output_dim = output_dim

        super(MyLayer, self).__init__(**kwargs)

    def build(self, input_shape):
        # Create a trainable weight variable for this layer.
        output_shape = self.compute_output_shape(input_shape)
        self.kernel = self.add_weight(name='kernel',
                                      shape=(1,) + output_shape[1:],
                                      initializer='ones',
                                      trainable=True)


        super(MyLayer, self).build(input_shape)  # Be sure to call this somewhere!

    def call(self, x):

        return K.tf.multiply(x, self.kernel)

    def compute_output_shape(self, input_shape):
        return (input_shape[0],self.output_dim)+input_shape[1:]

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