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laravel雄辩,总结来自链接表的多行

[英]laravel eloquent with sum multiple rows from linked table

I have a table Quotes that has a one-to-many relationship with the QuoteDetails table. 我有一个表Quotes具有与一个一对多的关系QuoteDetails表。

The table structure looks like this: 表结构如下所示:

return $this->quotes->with('quotedetails')
    ->orderBy('created_at', 'DESC')->paginate(10);

Results in: 结果是:

{
   "current_page":1,
   "data":[
      {
         "id":2,
         "subject":"demo",
         "quotedetails":[
            {
               "id":2,
               "quotes_id":2,
               "description":"testing data",
               "total":1080
            },
            {
               "id":3,
               "quotes_id":2,
               "description":"testing",
               "total":180
            }
         ]
      },
      {
         "id":1,
         "subject":"demo",
         "quotedetails":[
            {
               "id":1,
               "quotes_id":1,
               "description":"data",
               "total":360
            }
         ]
      }
   ],
   "per_page":10,
   "prev_page_url":null,
   "to":2,
   "total":2
}

I want to include the sum of quotedetails.total rather than the full list of QuoteDetails rows. 我想包括quotedetails.total的总和,而不是QuoteDetails行的完整列表。 I am not sure how this should be done. 我不确定应该怎么做。

Here is how I am querying in my model ( Quotes ) 这是我在模型中查询的方式( Quotes

public function quotedetails(){
        return $this->hasMany('App\Models\QuotesDetail', 'quotes_id', 'id');
    }

How can i get the total sum. 我如何能得到total金额。

Here is how i expect the output 这是我对输出的期望

{
   "current_page":1,
   "data":[
      {
         "id":2,
         "subject":"demo link data",
         "quotesum": 1260
      },
      {
         "id":1,
         "subject":"demo",
         "quotesum": 360
      }
   ],
   "per_page":10,
   "prev_page_url":null,
   "to":2,
   "total":2
} 
$query->withCount([
'quotedetail AS quotesum' => function ($query) {
            $query->select(DB::raw("SUM(total) as quotesum"));
        }
    ]);

I understand that you want to do it by query, But taking this without even query you'll be able to transform the paginated data this way, giving this example: 我知道你想通过查询来实现它,但是在没有查询的情况下,你可以通过这种方式转换分页数据,举个例子:

$quotes = Quotes::whereNotNull('id')->with('quotedetails')
    ->orderBy('created_at', 'DESC')->paginate();

//transform the data in the Paginate instance
$quotes->getCollection()->transform(function($quote){
     $quote->quotesum = $quote->quotedetails->sum('total');
     unset($quote['quotedetails']);
     return $quote;
});

The data in the paginated result is transformed and you have what you requested. 分页结果中的数据将被转换,并且您拥有所请求的内容。

Pro: More possibilities to do more with your response without adding any query. 专业:更多可能在不添加任何查询的情况下对您的响应做更多事情。

Con: More data in the result mean more work on the collection especially in case of large data. Con:结果中的更多数据意味着对集合的更多工作,尤其是在大数据的情况下。

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