在Linux中使用sed替换多个字符

Question

I have a variable in Linux like below. This is not a valid variable I just created to test how to replace characters with some new characters.

table=123~!@#$%^&*()+|}{:"?><-=[]\;',./

Want to replace all the special characters in this table variable like below

table1=123_____________________________

How can I do that in Linux?

Answer 1

Pipe it to sed and replace anything that is not ^ alphanumeric [:alnum:] with an underscore _ .

sed 's/[^[:alnum:]]/_/g'

In your code, this would look something like:

table1=$(echo table | sed 's/[^[:alnum:]]/_/g')

Answer 2

与tr相同

tr -c '[:alnum:]' _  <file