Pandas：ValueError：无法将浮点 NaN 转换为整数

Question

I get ValueError: cannot convert float NaN to integer for following:

df = pandas.read_csv('zoom11.csv')
df[['x']] = df[['x']].astype(int)

• The "x" is obviously a column in the csv file, but I cannot spot any float NaN in the file, and dont get what does it mean by this.
• When I read the column as String, then it has values like -1,0,1,...2000, all look very nice int numbers to me.
• When I read the column as float, then this can be loaded. Then it shows values as -1.0,0.0 etc, still there are no any NaN-s
• I tried with error_bad_lines = False and dtype parameter in read_csv to no avail. It just cancels loading with same exception.
• The file is not small (10+ M rows), so cannot inspect it manually, when I extract a small header part, then there is no error, but it happens with full file. So it is something in the file, but cannot detect what.
• Logically the csv should not have missing values, but even if there is some garbage then I would be ok to skip the rows. Or at least identify them, but I do not see way to scan through file and report conversion errors.

Update: Using the hints in comments/answers I got my data clean with this:

# x contained NaN
df = df[~df['x'].isnull()]

# Y contained some other garbage, so null check was not enough
df = df[df['y'].str.isnumeric()]

# final conversion now worked
df[['x']] = df[['x']].astype(int)
df[['y']] = df[['y']].astype(int)

Answer 1

For identifying NaN values use boolean indexing :

print(df[df['x'].isnull()])

Then for removing all non-numeric values use to_numeric with parameter errors='coerce' - to replace non-numeric values to NaN s:

df['x'] = pd.to_numeric(df['x'], errors='coerce')

And for remove all rows with NaN s in column x use dropna :

df = df.dropna(subset=['x'])

Last convert values to int s:

df['x'] = df['x'].astype(int)

Answer 2

ValueError: cannot convert float NaN to integer

From v0.24, you actually can. Pandas introduces Nullable Integer Data Types which allows integers to coexist with NaNs.

Given a series of whole float numbers with missing data,

s = pd.Series([1.0, 2.0, np.nan, 4.0])
s

0    1.0
1    2.0
2    NaN
3    4.0
dtype: float64

s.dtype
# dtype('float64')

You can convert it to a nullable int type (choose from one of Int16 , Int32 , or Int64 ) with,

s2 = s.astype('Int32') # note the 'I' is uppercase
s2

0      1
1      2
2    NaN
3      4
dtype: Int32

s2.dtype
# Int32Dtype()

Your column needs to have whole numbers for the cast to happen. Anything else will raise a TypeError:

s = pd.Series([1.1, 2.0, np.nan, 4.0])

s.astype('Int32')
# TypeError: cannot safely cast non-equivalent float64 to int32

Answer 3

Also, even at the lastest versions of pandas if the column is object type you would have to convert into float first, something like:

df['column_name'].astype(np.float).astype("Int32")

NB: You have to go through numpy float first and then to nullable Int32, for some reason.

The size of the int if it's 32 or 64 depends on your variable, be aware you may loose some precision if your numbers are to big for the format.

Answer 4

I know this has been answered but wanted to provide alternate solution for anyone in the future:

You can use .loc to subset the dataframe by only values that are notnull() , and then subset out the 'x' column only. Take that same vector, and apply(int) to it.

If column x is float:

df.loc[df['x'].notnull(), 'x'] = df.loc[df['x'].notnull(), 'x'].apply(int)

Answer 5

如果你有空值那么在做数学运算你会得到这个错误来解决它使用df[~df['x'].isnull()]df[['x']].astype(int)如果你想要你的数据集不可更改。