简体   繁体   English

语法CASE语句无效

[英]Invalid syntax CASE statement

I've been struggling all day with a really simple case statement in SQL... 我整天都在用SQL中的一个非常简单的case语句苦苦挣扎...

I have this piece of code: 我有这段代码:

UPDATE `alugueis`
    SET    `status` = CASE
             WHEN `pago_em` is null THEN 'Atrasado'
             WHEN `pago_em` is '' THEN 'Atrasado'
             ELSE `status`
           END
WHERE  `vencimento` <= CURDATE()

and the error I get is: [1064][42000]: (conn:235) You have an error in your SQL syntax; 我得到的错误是:[1064] [42000]:(conn:235)您的SQL语法有错误; check the manual ....... 检查手册.......

I don`t think I am mixing up the two forms of CASE, or am I? 我不认为我混淆了两种形式的CASE,还是我?

Thank you so much! 非常感谢!

I think you intend: 我认为您打算:

UPDATE alugueis
    SET status = (CASE WHEN pago_em is null THEN 'Atrasado'
                       WHEN pago_em = '' THEN 'Atrasado'
                       ELSE status
                  END)
    WHERE vencimento <= CURDATE();

The problem is the is '' . 问题是is ''

This would more normally be written without the CASE : 这通常在没有CASE下编写:

UPDATE alugueis
    SET status = 'Atrasado'
    WHERE vencimento <= CURDATE() AND
          (pago_em IS NULL OR pago_em = '')

You cannot use IS '' 您不能使用IS ''

UPDATE `alugueis`
    SET    `status` = CASE
             WHEN `pago_em` is null THEN 'Atrasado'
             WHEN `pago_em` = '' THEN 'Atrasado'
             ELSE `status`
           END
WHERE  `vencimento` <= CURDATE()

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM