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如何使用jt400 API仅检索启用了AS400的用户

[英]How to retrieve only AS400 Enabled Users using jt400 API

is there a possibility to retrieve only the Enabled Users -to add a filter- to the getUsers method of UserList of jt400? 是否只能检索jt400的UserList的getUsers方法的“已启用的用户”(添加过滤器)?

I did the following implementation but it does not have a good performance, so I am trying to find a better way and if there is a possibility to filter the users and to get only the Enabled users. 我执行了以下实现,但是它的性能不佳,因此,我试图找到一种更好的方法,是否有可能过滤用户并仅获取已启用的用户。

Set<String> as400Users = new HashSet(); 
AS400 as400 = new AS400(host, username, password);

//Retrieving Users
UserList users = new UserList(as400);
Enumeration io = users.getUsers();

  while (io.hasMoreElements()) {
            com.ibm.as400.access.User u = (com.ibm.as400.access.User)io.nextElement();
            String userName = u.getName();

            if (u.getStatus().equalsIgnoreCase("*ENABLED")) {
                as400Users.add(userName);
            }

        }

You could query the USER_INFO view like this: 您可以像这样查询USER_INFO视图:

select * 
from qsys2.user_info
where status = '*ENABLED'

This became available at v7.1. 从v7.1开始可用。 Note that this only provides users that you have authority to. 请注意,这仅提供您有权访问的用户。

You also might want to move the getName() call inside the filter: 您可能还想将getName()调用移到过滤器中:

Set<String> as400Users = new HashSet(); 
AS400 as400 = new AS400(host, username, password);

//Retrieving Users
UserList users = new UserList(as400);
Enumeration io = users.getUsers();

while (io.hasMoreElements()) {
    com.ibm.as400.access.User u = (com.ibm.as400.access.User)io.nextElement();

    if (u.getStatus().equalsIgnoreCase("*ENABLED")) {
        as400Users.add(u.getName());
    }

}

Or you could use the newer foreach syntax with getUsers(-1,0) 或者您可以对getUsers(-1,0)使用更新的foreach语法

Set<String> as400Users = new HashSet(); 
AS400 as400 = new AS400(host, username, password);

//Retrieving Users
UserList users = new UserList(as400);
for (com.ibm.as400.access.User u: users.getUser(-1,0)) {
    if (u.getStatus().equalsIgnoreCase("*ENABLED")) {
        as400Users.add(u.getName());
    }
}

Now just choose the fastest method. 现在只需选择最快的方法。

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