如果未使用javascript定义元素，则从嵌套数组中删除数组对象

Question

Raw array

myArr = [
{name:'abcd',values:[undefined,{quarter: "Q2-2016", koordinaten: 119},{quarter: "Q3-2016", koordinaten: 129},undefined]},
{name:'abcd',values:[undefined,undefined,{quarter: "Q4-2016", koordinaten: 19},undefined]}
]

Expected array,

 myArr = [
        {name:'abcd',values:[{quarter: "Q2-2016", koordinaten: 119},{quarter: "Q3-2016", koordinaten: 129}},
        {name:'abcd',values:[{quarter: "Q4-2016", koordinaten: 19}]}
        ]

i want to remove undefined element with index in result array,

Answer 1

Try map and filter

myArr.map( s => (s.values = s.values.filter( p => JSON.stringify(p) != "{}" ), s ) );

Demo

 var myArr = [ {name:'abcd',values:[{undefined},{quarter: "Q2-2016", koordinaten: 119}, {quarter: "Q3-2016", koordinaten: 129},{undefined}]}, {name:'abcd',values:[{undefined},{undefined},{quarter: "Q4-2016", koordinaten: 19},{undefined}]} ]; var output = myArr.map(s => (s.values = s.values.filter(p => JSON.stringify(p) != "{}"), s)); console.log(output); 

Answer 2

This should do the trick, you basically need to remove all the undefined values by looping through them.

 myArr = [ {name:'abcd',values:[undefined,{quarter: "Q2-2016", koordinaten: 119},{quarter: "Q3-2016", koordinaten: 129},undefined]}, {name:'abcd',values:[undefined,undefined,{quarter: "Q4-2016", koordinaten: 19},undefined]} ] myArr.forEach(arrItem => { arrItem.values = arrItem.values.filter(x => !!x); }); console.log(myArr); 

Answer 3

You could filter falsy values (like undefined ) with Array#filter and Boolean as callback.

 var array = [{ name: 'abcd', values: [undefined, { quarter: "Q2-2016", koordinaten: 119 }, { quarter: "Q3-2016", koordinaten: 129 }, undefined] }, { name: 'abcd', values: [undefined, undefined, { quarter: "Q4-2016", koordinaten: 19 }, undefined] }]; array.forEach(function (o) { o.values = o.values.filter(Boolean); }); console.log(array); 

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Answer 4

You can use, underscore for such kind of tasks.

Compact method

 myArr = [{ name: 'abcd', values: [undefined, { quarter: "Q2-2016", koordinaten: 119 }, { quarter: "Q3-2016", koordinaten: 129 }, undefined] }, { name: 'abcd', values: [undefined, undefined, { quarter: "Q4-2016", koordinaten: 19 }, undefined] }] // Cleansed Array myArr = myArr.map(function(arrItem) { arrItem.values = _.compact(arrItem.values); return arrItem }) 

 <script src="https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.8.3/underscore-min.js"></script>