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如何使用javascript遍历json对象并形成具有连接值的新对象?

[英]How to iterate through json object and form a new object with concatenated values using Javascript?

I have been working on api which gives data in JSON object and i have no control with it at all. 我一直在使用api来提供JSON对象中的数据,而我却完全无法控制它。 I need to pull data on select box. 我需要在选择框上提取数据。 I have managed to populate it but it allows single value binding only. 我设法填充它,但它只允许单值绑定。 ie firstName or lastName or middleName and not both. 即firstName或lastName或middleName两者都不是。 Here is my current JSON Object: 这是我当前的JSON对象:

.employeesList = [
  {
    id: 1,
    firstName: 'firstName',
    middleName: 'middleName',
    lastName: 'lastName',
  },
  {
    id: 2,
    firstName: 'firstName2',
    middleName: 'middleName2',
    lastName: 'lastName2',
  },
  {
    id: 3,
    firstName: 'firstName3',
    middleName: 'middleName3',
    lastName: 'lastName3',
  },
  {
    id: 4,
    firstName: 'firstName4',
    middleName: 'middleName4',
    lastName: 'lastName4',
  },
  {
    id: 5,
    firstName: 'firstName5',
    middleName: 'middleName5',
    lastName: 'lastName5',
  }
]

I would like to merge firstName, middleName and lastName in each data and form a new JSON Object having only ids and fullNames like so: 我想在每个数据中合并firstName,middleName和lastName并形成一个仅具有id和fullNames的新JSON对象,如下所示:

.employeesList = [
  {
    id: 1,
    fullName: 'firstName MiddleName LastName'
  },
  {
    id: 2,
    fullName: 'firstName2 MiddleName2 LastName2'
  },
  {
    id: 3,
    fullName: 'firstName3 MiddleName3 LastName3'
  },
  {
    id: 4,
    fullName: 'firstName4 MiddleName4 LastName4'
  },
  {
    id: 5,
    fullName: 'firstName5 MiddleName5 LastName5'
  }
]

How can i achieve that using Javascript? 如何使用Javascript实现该目标?

Use array.prototype.map : 使用array.prototype.map

 var employeesList = [ { id: 1, firstName: 'firstName', middleName: 'middleName', lastName: 'lastName', }, { id: 2, firstName: 'firstName2', middleName: 'middleName2', lastName: 'lastName2', }, { id: 3, firstName: 'firstName3', middleName: 'middleName3', lastName: 'lastName3', }, { id: 4, firstName: 'firstName4', middleName: 'middleName4', lastName: 'lastName4', }, { id: 5, firstName: 'firstName5', middleName: 'middleName5', lastName: 'lastName5', } ]; var newEmployeesList = employeesList.map(e => ({id: e.id, fullName: `${e.firstName} ${e.middleName} ${e.lastName}`})); console.log(newEmployeesList); 

 var employeesList = [ { id: 1, firstName: 'firstName', middleName: 'middleName', lastName: 'lastName', }, { id: 2, firstName: 'firstName2', middleName: 'middleName2', lastName: 'lastName2', }, { id: 3, firstName: 'firstName3', middleName: 'middleName3', lastName: 'lastName3', }, { id: 4, firstName: 'firstName4', middleName: 'middleName4', lastName: 'lastName4', }, { id: 5, firstName: 'firstName5', middleName: 'middleName5', lastName: 'lastName5', } ] employeesList.map((obj) => { obj["fullName"] = obj["firstName"] + " " + obj["middleName"] + " " +obj["lastName"]; delete obj["firstName"]; delete obj["middleName"]; delete obj["lastName"]; console.log(obj) }); 

newList = employeesList.map((empl) => {
    return {
        id: empl.id, fullName: empl.firstName + ' ' + empl.middleName + ' ' + empl.lastName}
    }
)

I use this code and work fine for me. 我使用此代码,对我来说工作正常。 (need JQuery). (需要JQuery)。

var newEmployeesList = [];
$.each(employeesList, function(key, item) {

    var f_name = item.firstName;

    var m_name = item.middleName;

    var l_name = item.lastName;

    var obj = new Object();
    obj.id = key;
    obj.fullName = f_name + " " + m_name + " " + l_name;

    newEmployeesList.push(obj);

});

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