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如何计算缓存中的总字节数？

[英]how to calculate total bytes in cache?

原文 2017-11-17 13:22:54 9 1 caching/ computer-science/ processor

I have the question does anyone know how calculate the total amount of bytes in cache if the byte main memory is 2 MB and the block size is 32 Bytes. 我有一个问题，如果字节主内存为2 MB，块大小为32字节，是否有人知道如何计算缓存中的字节总数。 Using direct mapping with 32 lines? 使用32行直接映射？

Really hard to understand what and how it is done. 真的很难理解它是如何完成的。

Thanks. 谢谢。

1 个解决方案

The purpose here is to cache some of the data the processor needs in memory. 此处的目的是将处理器需要的某些数据缓存在内存中。 Similarly, there may be a cache between the data in the memory and the disk. 同样，内存和磁盘中的数据之间可能存在高速缓存。

In this case, if a data is needed from the disk, the faster memory can be loaded into the memory by booting. 在这种情况下，如果需要磁盘上的数据，则可以通过引导将更快的内存加载到内存中。 There are of course two possibilities: Hit: hit, cache of the processor's request Miss: lost, access to the memory of the processor's request can not be made from the cache. 当然有两种可能：命中：命中，处理器请求的缓存未命中：丢失，无法从缓存访问处理器请求的内存。

The ratios of these numbers also have the following values: hit ratio = hit / hit + miss) Miss ratio = miss / total demand (or hit + loss) For example, suppose that 45 memory access requests and 21 of them are in cache. 这些数字的比率还具有以下值：命中率=命中/命中+丢失）命中率=命中/总需求（或命中+丢失）例如，假设45个内存访问请求中有21个在缓存中。

In this case, miss = 45 - 21 = 24 hit ratio = 21/45 = 47% loss ratio = 24/45 = 53% 在这种情况下，未击中= 45-21 = 24命中率= 21/45 = 47％损失率= 24/45 = 53％

#can you put a plus? ＃你能加一个吗？