[英]How to edit this MySQL query to include an extra column with count and avg?
This query: 该查询:
select p.visitor_id , p.url, avg(p.duration), count(*) as sum_pages
from pages p
where visitor_id = 1
group by p.visitor_id , p.url
having avg(p.duration) > (select avg(p2.duration)
from pages p2
where p2.visitor_id = p.visitor_id
);
produces this hypothetical table: 产生此假设表:
visitor_id ---- url ---- duration --- sum_pages
1 ------------ home ------- 5 ------- 20
1 ------------ about ------ 8 ------- 12
1 ------------ contact ---- 2 ------- 13
1 ------------ services --- 2 ------- 18
What it does: Takes the average duration number of the whole table, and checks if the average duration URL is greater. 它的作用:获取整个表的平均持续时间数,并检查平均持续时间URL是否更大。 If yes, it displays the number. 如果是,则显示数字。
I want to do the same thing and this time to add the pageviews. 我想做同样的事情,这次添加页面浏览量。 Each row is counted as a pageview. 每行都计为一次网页浏览。
How do I achieve this? 我该如何实现?
I found a way to achieve this but not sure about the performance of the query: 我找到了一种方法来实现此目的,但不确定查询的性能:
select
visitor_id,
url,
sum(duration),
avg(duration),
count(*) as sum_pages
from pages p
where visitor_id='1'
group by visitor_id,url
having sum(duration) > (select avg(duration)
from pages
where visitor_id=p.visitor_id
)
and sum_pages > (select count(*)/(select count(distinct url) from pages where visitor_id=p1.visitor_id)
from pages p1
where p1.visitor_id=p.visitor_id
)
;
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