将元组添加到列表中，而无需打开元组

Question

In Python, I have some tuples like b, and I want to add them into an empty list without unpack them. Here, I simplify b so that it repeats itself, in reality, the values in b would be different, so b would be b1, b2, b3...

b = ({'a': 1, 'b': 1, 'c': 1}, 'y')
bb = [b, b, b]
print(len(bb))
print(len(bb[0]))
bb

This gives

3 2 Out[204]: [({'a': 1, 'b': 1, 'c': 1}, 'y'),  ({'a': 1, 'b': 1,'c': 1}, 'y'),  ({'a': 1, 'b': 1, 'c': 1}, 'y')]

which is what I want. But since I am now doing in a loop, I can not write bb = [b, b, b]. The syntax I came up with will make hiarachy that I do not want.

bb = ()
b = ({'a': 1, 'b': 1, 'c': 1}, 'y')
bb = [bb, b] 
# in reality I loop bb with 3 times in for loop
bb = [bb, b]
bb = [bb, b]
print(len(bb))
print(len(bb[0]))
bb

This gives

[[[(), ({'a': 1, 'b': 1, 'c': 1}, 'y')], ({'a': 1, 'b': 1, 'c': 1},'y')],  ({'a': 1, 'b': 1, 'c': 1}, 'y')]

and is not want I wanted. How can I loop and reach the first outcome?

Answer 1

Just use list comprehension:

b = ({'a': 1, 'b': 1, 'c': 1}, 'y')
bb = [b for i in range(3)]

Output:

[({'a': 1, 'c': 1, 'b': 1}, 'y'), ({'a': 1, 'c': 1, 'b': 1}, 'y'), ({'a': 1, 'c': 1, 'b': 1}, 'y')]

Answer 2

Start with a list and use append :

bb = []
b = ({'a': 1, 'b': 1, 'c': 1}, 'y')
for _ in range(3):
    bb.append(b)