[英]Is there a NODE_ENV equivalent in Python
Is there a NODE_ENV equivalent in Python? Python中是否有等效的NODE_ENV?
I want to dynamically load JSON configurations to the python application based on the executing environment. 我想根据执行环境将JSON配置动态加载到python应用程序。 In nodeJs, I do this by using the process.env.NODE_ENV.
在nodeJs中,我通过使用process.env.NODE_ENV来执行此操作。
For example, 例如,
I start the app like this, 我这样启动应用程序
NODE_ENV=production node server.js
And use the variable in the application like this, 并像这样在应用程序中使用变量,
if(process.env.NODE_ENV == "production") {
// Load the production config file here (eg: database.json)
} else {
// Load the development config file here (located in a different directory)
}
How can I achieve the same in Python? 如何在Python中实现相同目标? Or can I make use of python virtualenv or python setuptools to have a workaround?
或者我可以利用python virtualenv或python setuptools来解决问题吗?
For starters, you could do something like this. 对于初学者,您可以执行以下操作。
import os
env = os.environ.get("PYTHON_ENV")
if(env =="production"):
//
else :
The script can be run with PYTHON_ENV="production" python myscript.py
. 可以使用
PYTHON_ENV="production" python myscript.py
运行脚本。 Or you could use some library like dotenv( https://github.com/theskumar/python-dotenv ). 或者您可以使用诸如dotenv( https://github.com/theskumar/python-dotenv )之类的库。
您可以在python pip install environs
尝试environs库
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