想要将一个表的最后插入的ID插入laravel 5中的另一个表

Question

Want to insert the latest inserted one table's id into another table.

Suppose there are two tables transactions and user_transactions . Now I want to store data in transaction table and also want to store the last inserted transactions table id into another table user_transactions . Do all part in one function.

Here is my store function code where I want to do the above job.

public function store(Request $request)
{
    $data = new transaction;
    $data->title_id = $request->title_id;
    $data->transaction_type_id = '2';
    $data->amount = $request->amount;
    $data->save();

    $data_of_user_transaction = new user_transaction;
    $data_of_user_transaction->transaction_id = $data->id;
    $data_of_user_transaction->user_id = session('user_info.id');
    $data_of_user_transaction->save();
}

After did the code data is inserted in transactions table but not inserted in user_transactions table.

Answer 1

I have got my answer . I didn't use user_transaction model at the top of my code.

Just add the below line at the top of my code.

use App\user_transaction;

Given store function code is totally okay.

Answer 2

Do like this i have Auction Table and Rule table I want Auction to save both tables in same time but I want to store Auction_id in Rule Table Column so i did this and get an appropriate answer...

public function store(Request $request,$id)
{
    $auction = new Auction();
    $auction->products_id= $id;
    $auction->auc_price=$request->input('price');
    $auction->r_price=$request->input('rprice');
    $auction->from=$request->input('date');
    $auction->to=$request->input('todate');
    $auction->auc_status= 1;
    $auction->save();
    $rules= new Rule();

    $rules->auction_id = $auction->id;
    $rules->from=$request->input('from');
    $rules->to=$request->input('to');
    $rules->gap=$request->input('gap');

    $rules->save();

  return back();


}