Python：正则表达式在匹配项之间进行匹配

Question

Text file output has syntax in a form of word> data <word , where the need is to remove the brackets. The data part can be pretty much anything (and of variable length), including new line, spaces, dots, letters etc. Currently i am using...

text = re.sub("(>)(.{1,10})(<)", r"\2", text)

...but it has obvious limitations, 1 being length. The reason for not using * is because there are some restrictions, namely:

• no other > or < can be present inside the match except for its boundaries
• only 1 number inside the match can form a pattern of single digits, that is dog> 7 4^ 8 0 . 2 1 6? <cat dog> 7 4^ 8 0 . 2 1 6? <cat dog> 7 4^ 8 0 . 2 1 6? <cat & exam> 1961 5 . 66 9 <ple exam> 1961 5 . 66 9 <ple shall not match, while test> 0? <string test> 0? <string or over> 1980 31, 6 000 <flow are fine and brackets shall be removed

How can this be approached?

Answer 1

Why not like this?

text = re.sub(r">((?:[^<>\d]|\d{2,})*)<", r"\1", text)

(?:[^<>\\d]|\\d{2,})* matches either any character except angle brackets or digits ( [^<>\\d] ) or any digits as long as there are at least two ( \\d{2,} ), repeatedly ( * ).

Answer 2

Since none of the answerers added to their answers after the one edit of the question, i had to post another question to answer that part and actually finish the regexp.

At last, the final code i'm using is this:

text = re.sub(r">((?!(?:[^<]*\\b\\d\\b){2})[^><]*)<", r"\\1", text)

It allows for only 1 single digit number and no brackets inside the match, but otherwise catches anything else.