使用新值更新现有的JS关联数组

Question

I want to search 3.30pm in below array and update the type value of the array index in JS

0: {time: "2:00pm",type:16}
1: {time: "3:30pm",type:30}
2: {time: "5:00pm",type:90}

Any one please suggest the correct way to fix it.

I tried this..

 function in_array(array, id) {
    console.log(array);
    for(var i=0;i<array.length;i++) {
        return (array[i][0].time === id)
    }
    return false;
}
$result = in_array(timesShow, $time);

But its returning error like

movies:620 Uncaught TypeError: Cannot read property 'time' of undefined

Answer 1

使用Array＃Filter

return array.filter(x=>x.time==id).length > 0

Answer 2

Try this...

for(var i=0;i<array.length;i++) {
   if(array[i].time === id)
   {
       array[i].type='whatever you want to change';
   }
}

Answer 3

 var obj = [ {time: "2:00pm",type:16}, {time: "3:30pm",type:30}, {time: "5:00pm",type:90} ]; obj.forEach(function(ob){ if(ob.time == "3:30pm") ob.type = 50; }); console.log(obj) 

Loop through array object using forEach , then check with the time value if matches change type of same object.

Answer 4

You could use just the item without another index and return the item, if found.

 function getItem(array, id) { var i; for (i = 0; i < array.length; i++) { if (array[i].time === id) { return array[i]; } } } var timesShow = [{ time: "2:00pm", type: 16 }, { time: "3:30pm", type: 30 }, { time: "5:00pm", type: 90 }]; console.log(getItem(timesShow, "3:30pm")); console.log(getItem(timesShow, "2:30pm")); 

ES6 with Array#find

 function getItem(array, id) { return array.find(o => o.time === id); } var timesShow = [{ time: "2:00pm", type: 16 }, { time: "3:30pm", type: 30 }, { time: "5:00pm", type: 90 }]; console.log(getItem(timesShow, "3:30pm")); console.log(getItem(timesShow, "2:30pm")); 

Answer 5

Try this:

    var obj = [
     {time: "2:00pm",type:16},
     {time: "3:30pm",type:30},
     {time: "5:00pm",type:90}
    ];
    var finalResult = obj.filter(function(d){
     if(d.time == "3:30pm"){d['type'] = 40}
     return d;
    });
console.log(finalResult)