当我使用bash运行程序时，C fopen无法正常工作

Question

I have simple bash script

#!/bin/bash

make
./code1_test/test_syn1
./code2_test/test_syn2
./code3_test/test_syn3

test_syn are my program tests. In every of these programs, I'm using fopen command to open .txt file. If I run programs from command line, I have a correct test output, but when I'm using this bash script, fopen return me NULL, so I can't open my .txt files and I can't run tests. Why is this happening, and how can I fix this?

Answer 1

If you're using fopen() with a relative path, you should execute the script from its directory. Try this:

#!/bin/bash
make
(cd code1_test/ && exec ./test_syn1)
(cd code2_test/ && exec ./test_syn2)
(cd code3_test/ && exec ./test_syn3)

Otherwise your program tries to open your .txt in the directory from where your run your Bash script, that's not what you want.

If you want to be able to run your program from anywhere, you might try not to use a relative path when you fopen() .