qt base64编码/解码添加转义字符

Question

I have a method that returns an unsigned char * array and I am trying to encode this as base64 and decode it later. So what I am doing is as follows:

unsigned char * val = myMethod();
char * encodedMsg = reinterpret_cast<char *>(val);
std::cout << "Returned message: " << val << std::endl;
QByteArray raw = QByteArray(encodedMsg).toBase64(QByteArray::Base64Encoding | QByteArray::OmitTrailingEquals);

The output from the method is \
z\\ri!i, and the encoded value is XHUwMDAxelxyaSFpLA .

Now, I decode it as follows:

QByteArray decoded = QByteArray::fromBase64(raw,
                            QByteArray::Base64Encoding | QByteArray::OmitTrailingEquals);

qDebug() << decoded;

Now this returns \\\
z\\\\ri!i, . Notice that the slashes have been escaped.

I know I can replace this as a post processing step but is there a way to avoid this. Perhaps I am using the encoding/decoding incorrectly?

Answer 1

Try like below,

Base 64 Encode :

unsigned char* Ciphertext = Encypt(); QByteArray qByteArray((char*)(Ciphertext),(int)strlen((char *)Ciphertext)); qDebug()<<"Ciphertext : "<< qByteArray.toBase64();

Output :

Ciphertext :  "WLdC+ri94z940BiAven6qXQH6rPbE64nQXt5aFByLGPFh1n//tOGLG02zBSoZ79qMA"

Base 64 Decode :

QString data = QString::fromLatin1(QByteArray::fromBase64(Base64QByteArray.toBase64()).data());

in my case i used this base64 conversion for AES encyption, make it shoultable for yours.