单击 AppBar 打开抽屉

Question

If you create an Scafold there is an option for drawer. If you now create this drawer you get automaticly the menu icon on the leading position of the appbar. But i want an other icon there which opens the drawer. I tried to make an iconbutton myself on the leading position but this button can't open the drawer even with „Scafold.of(context).openDrawer()“ it can't open it.

Is there any option to replace the icon for the drawer button?

Answer 1

Use a Key in your Scaffold and show the drawer by calling myKey.currentState.openDrawer() , here is a working code:

import "package:flutter/material.dart";

class Test extends StatefulWidget {
  @override
  _TestState createState() => new _TestState();
}

class _TestState extends State<Test> {
  final GlobalKey<ScaffoldState> _scaffoldKey = new GlobalKey<ScaffoldState>();

  @override
  Widget build(BuildContext context) {
    return new Scaffold(
      key: _scaffoldKey,
      drawer: new Drawer(),
      appBar: new AppBar(
        leading: new IconButton(
          icon: new Icon(Icons.settings),
          onPressed: () => _scaffoldKey.currentState.openDrawer(),
        ),
      ),
    );
  }
}

Answer 2

Alternative to the accepted answer which does not require a GlobalKey :

class _TestState extends State<Test> {
  @override
  Widget build(BuildContext context) {
    return new Scaffold(
      drawer: new Drawer(),
      appBar: new AppBar(
        leading: Builder(
        builder: (context) => IconButton(
            icon: new Icon(Icons.settings),
            onPressed: () => Scaffold.of(context).openDrawer(),
          ),
        ),
      ),
    );
  }
}

Answer 3

Using GlobalKey:

final GlobalKey<ScaffoldState> _key = GlobalKey(); // Create a key

@override
Widget build(BuildContext context) {
  return Scaffold(
    key: _key, // Assign the key to Scaffold.
    drawer: Drawer(),
    floatingActionButton: FloatingActionButton(
      onPressed: () => _key.currentState!.openDrawer(), // <-- Opens drawer
    ),
  );
}

Using Builder:

@override
Widget build(BuildContext context) {
  return Scaffold(
    drawer: Drawer(),
    floatingActionButton: Builder(builder: (context) {
      return FloatingActionButton(
        onPressed: () => Scaffold.of(context).openDrawer(), // <-- Opens drawer.
      );
    }),
  );
}

Answer 4

you need initialize scaffoldKey after that,

Open drawer and close drawer

 GestureDetector(
          onTap: () {
            if(scaffoldKey.currentState.isDrawerOpen){
              scaffoldKey.currentState.openEndDrawer();
            }else{
              scaffoldKey.currentState.openDrawer();
            }
          },
          child:  LeadingIcon(icon: Icons.menu),//your button
        ),