如何制作一个可以用文件打开的程序？ （蟒蛇）

Question

I was making a program that opens a file and does a few things to it, and I wondered if there was a way that you could click on a file, and it would open it in the program, instead of going into the program, clicking open, and navigation through the files to find it, or just a way where you can click "Open With..." and select your program. Here is the code if it helps:

from tkinter import *
from tkinter import filedialog
from subprocess import *
import os

root = Tk()
root.title("Snake converter")
def open_file():

    filename = filedialog.askopenfilename(filetypes = (("Snake files", "*.sim"),("Python Files", "*.py"),("All files", "*.*")))
    filenametmp = filename + ".tmp"
    print filename + " is being compiled. Please wait..."
    tf = open(filenametmp, "a")
    f = open(filename, "r")
    filecontents = f.read()
    tf.write("from simincmodule import *" + "\n")
    tf.write(filecontents)
    os.chdir("C:\Snake\info\Scripts")
    print os.getcwd()
    call(["pyinstaller", filenametmp])
    os.remove("C:/Snake/info/Scripts/build")
    f.close()
    tf.close()
    print "\n\n----------------------------------------------------------------------\n\nFinished compiling " + filename + ". Find the program under [filename]/[filename].exe"

openbutton = Button(root, text = "Open", width = 10, command = open_file)
openbutton.pack()

root.mainloop()

Any help or suggestion will be highly appreciated.

Thanks!

Answer 1

"Open with..." usually sends the pathname of the file to sys.argv . So at an appropriate place of your program, add this:

if len(sys.argv) > 1:
    open_file(sys.argv[1])

(As I said in the comment, you really want to let your open_file take an argument, and have another function like open_file_dialog to open the dialog.)

That leaves the question of how to make something you can "Open with..." in the first place. If you are on Windows, you should be able to achieve finer control with file association by editing the registry: see this MSDN page for details.

Alternatively, a quick-and-dirty way to do it is to make a .bat script that takes an argument and passes it to your python program. I remember doing this some time ago, but I haven't used Windows seriously for a long time, so I can't tell you how to write the script right off my head.

Answer 2

I am a Fan of Autohotkey Tools And Python Launguages,

An Other Way to do it, is:

If you want to run a program, and then Want to opened it with a file ("Open With...")

You can Think about,

Making your own Computer Movements Scripts With Keyboard Shortcuts Macros.

Step 1: Install (Python27) on your Windows System. Click Here

Step 2: Then Install the Python Packages - pyautogui and pywinauto

You can Use this Msdos Batch Script:

Install.bat

C:\Python27\scripts\pip.exe install pyautogui
pause
C:\Python27\scripts\pip.exe install pywinauto
pause

Now You are Ready, To Make and use this Python Script:

Example1.pyw

#run Notepad with "Open..." 
#######################
import pywinauto
pywinauto.Application().start(r"C:\Windows\System32\Notepad.exe c:\test\test.txt")
#######################

Example2.pyw

#run Notepad
#######################
import pywinauto
pywinauto.Application().start("C:\Windows\System32\Notepad.exe")
#######################


#Open a File - "Open With..." 
#######################
import pyautogui
import time
time.sleep(2)
pyautogui.hotkey('ctrl','o') #Many Programs use Shortcut Ctrl+o to "Open With..." 
time.sleep(.750)
pyautogui.typewrite('c:\\test\\test.txt',0)
time.sleep(2)
pyautogui.hotkey('enter')
#######################

# you can send any text or Keyboard Shortcuts Combinations - Example Copy - pyautogui.hotkey('ctrl', 'c')

Note: If you use a File Path with typewrite Command - You Can Not put a ( single backslash \\ ) you must replace it into a ( double backslash \\\\ )

Tip : Python Languages together with AutoPythonlauncher Software is a good Combination - If You Want to make, Toolbars On your Windows Desktop - Executeable Pictures with Python Scripts For Mouse or Touch Device. - For more info look at Homepage

Answer 3

How I would do it:

1. Make it so that your program reads from stdin and writes to stdout
2. Use the power of the shell. If you are in a unix shell, just simply do cat infile | ./python myProgram.py > outfile cat infile | ./python myProgram.py > outfile

This will give the contents of infile to your program on stdin, then write the output of stdout to outfile .