蟒蛇。 通过分割字符串键对字典排序

Question

I have a list of dicts like this:

my_list=[{'c': '1/2014'},
{'c': '1/2015'},
{'c': '10/2014'},
{'c': '2/2014'},
{'c': '3/2014'},
{'c': '1/2011'},
{'c': '2/2011'},
{'c': '3/2011'},
{'c': '6/2014'},
{'c': '5/2014'},
{'c': '10/2014'},
{'c': '2/2015'},
{'c': '4/2015'},
{'c': '3/2015'},
{'c': '5/2016'},
{'c': '1/2017'}]

I want order my list by the c key. The key have two parts: year_counter / year, so first I have to order by year and then by year_counter, inside each year gruop. At the end I expect to have this:

my_list=[{'c': '1/2011'},
 {'c': '2/2011'},
 {'c': '3/2011'},
 {'c': '1/2014'},
 {'c': '2/2014'},
 {'c': '3/2014'},
 {'c': '5/2014'},
 {'c': '6/2014'},
 {'c': '10/2014'},
 {'c': '1/2015'},
 {'c': '2/2015'},
 {'c': '3/2015'},
 {'c': '4/2015'},
 {'c': '11/2015'},
 {'c': '5/2016'},
 {'c': '1/2017'}]

What is the best efficent way to achieve this?

Answer 1

I think idea should be to split this month and year first then apply some sorting algorithm to sort it.

you can use the underscore library for that. notice my fiddle

https://jsfiddle.net/stdeepak22/96trt0r4/1/

first I splitted your value of c to month and year.

var split_list = _.map(my_list, function(r){
    return {
      mn : parseInt(r.c.split('/')[0]),
      yr : parseInt(r.c.split('/')[1])
    };
  }); 

then I apply sorting then again joining back to actual field c value

var sorted_list= _.chain(split_list)
  .sortBy(function(f)
  {
    return f.mn;
  }).sortBy(function(f)
  {
    return f.yr;
  }).map(function(obj)
  {
    return { c: obj.mn+'/'+obj.yr }
  }).value();

then I printed on console to check the output.

console.log(sorted_list);

Initially I forgot to parse the month and year value to int. that I have corrected now.

UPDATE Initially you didn't tag, Python I thought you are looking for json, so I provided the JavaScript solution.