[英]How does Task.Delay work exactly?
They say Task.Delay() is an async Thread.Sleep(). 他们说Task.Delay()是一个异步的Thread.Sleep()。 To test this I wrote below code.
为了测试这个我写下面的代码。 I expect to print immediately "One" then 3 seconds later result variable (15) will be printed.
我希望立即打印“One”,然后3秒后打印结果变量(15)。 2 seconds after this, "Two" will be printed.
在此之后2秒,将打印“Two”。 But it doesnt seem so.
但它似乎并非如此。 "One" is not immediately printed.
“One”不会立即打印出来。 "One" is printed 3 seconds later.
3秒后打印“One”。 Why does it wait 3 seconds to print "One" ?
为什么要等3秒钟打印“One”?
using System;
using System.Threading;
using System.Threading.Tasks;
namespace ConsoleApplication31
{
class Program
{
public static int Multiply(int a, int b)
{
return a * b;
}
public static async Task DoRunAsync(int m, int n)
{
int result = await Task.Run(() => Multiply(m, n));
await Task.Delay(3000);
Console.WriteLine("One");
Console.WriteLine(result);
}
static void Main(string[] args)
{
Task t = DoRunAsync(3, 5);
Thread.Sleep(5000);
Console.WriteLine("Two");
}
}
}
Modifying your DoRunAsync
method as follows will make things work as intended: 如下修改
DoRunAsync
方法将使事情按预期工作:
public static async Task DoRunAsync(int m, int n)
{
int result = await Task.Run(() => Multiply(m, n));
Console.WriteLine("One"); // before the delay, not after...
await Task.Delay(3000);
Console.WriteLine(result);
}
Your code behaves as follows: 您的代码行为如下:
await Task.Delay(3000); // Await 3 seconds...
Console.WriteLine("One"); // Once you are done awaiting, print the string...
If you await before printing the string, you can't expect it to be printed immediately... 如果您在打印字符串之前等待,则不能指望它立即打印...
It takes 3 seconds to print "One"
because you await
-ed Task.Delay
too soon. 打印
"One"
需要3秒钟,因为你很快就await
Task.Delay
。
Change the code as follows to get the result that you expected: 更改代码如下,以获得您期望的结果:
int result = await Task.Run(() => Multiply(m, n));
var taskDelay = Task.Delay(3000); // No blocking here, so
Console.WriteLine("One"); // printing can proceed.
await taskDelay; // This causes a block for the remainder of 3 seconds
Console.WriteLine(result);
When you start the delay task prior to printing "One"
without await
-ing it, subsequent WriteLine
could complete without a delay. 当您在打印
"One"
之前启动延迟任务而不await
它时,后续的WriteLine
可以在没有延迟的情况下完成。
The job of await
is to suspend the current method until whatever awaitable you pass to it is complete . await
的工作是暂停当前方法,直到您传递给它的任何等待完成为止。 How, why and when that awaitable was created and started are of no relevance to what the await
keyword accomplishes. 创建和启动
await
,原因和时间与await
关键字的完成无关。
I think you're under the impression that await
starts something, when in fact it's the opposite - it marks a point in your code where you wait for something to finish . 我认为你的印象就是
await
开始了,事实上它恰恰相反 - 它标志着你在等待某些事情完成的代码中的一个点。
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