bash从bash命令更新mysql

Question

I want to update database from bash command:

#!/bin/bash
list= cat /home/wwwroot/list.txt;
mysql -u root -D dbname -e "UPDATE wp_postmeta SET meta_value = '$list' WHERE meta_key = 1";

cat /home/wwwroot/list.txt
text1
text2
text3
...

How to $list variable can be read in sql query?

Thank you.

Answer 1

Cat is an overkill here.

---

I suggest using an array if you need space delimited values.

list=($(</home/wwwroot/list.txt))
mysql -u root -D dbname -e "UPDATE wp_postmeta \
SET meta_value = '${list[@]}' WHERE meta_key = 1";

The advantage here is if you need comma separated values then you could employ bash [ parameter substitution ] to achieve your feet. Just change the query to

mysql -u root -D dbname -e "UPDATE wp_postmeta \
SET meta_value = '${list[@]/%/,}' WHERE meta_key = 1";
#Note ${list[@]/%/,} appends comma after each value in the text file

All good :-)