[英]How to try different function, and return first output that succeds in python?
I have a couple of different functions, that each outputs a json
string if successful. 我有几个不同的函数,如果成功,每个函数都会输出一个
json
字符串。 I cannot know beforehand whether they will fail or not so I want have to try them all in the order specified below. 我无法事先知道它们是否会失败,因此我想按以下指定的顺序全部尝试它们。 How can I do this?
我怎样才能做到这一点?
I have tried things like: 我已经尝试过类似的事情:
import func1
import func2
import func3
def compi(url):
try:
return func1(url)
except:
return func2(url)
else:
return func3(url)
I am certain that func3
will not fail. 我确信
func3
不会失败。
def compi(url):
functions = [func1, func2, func3]
for func in functions:
try:
return func(url)
except:
pass
#oops, none of them succeeded.
raise Exception("All functions failed to return a value.")
Python functions are first-class objects, so instead of going through them manually, you can just make a list of them and loop through it, like so: Python函数是一流的对象,因此您无需列出它们并手动遍历它们,而无需手动进行操作,如下所示:
tested_funcs = [f1, f2, f3]
for f in tested_funcs:
result = f(someinput)
if result: break
return result
Wrap the inner block in a try/catch if it throws an error upon failing. 如果内部块在失败时引发错误,则将其包装在try / catch中。
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