[英]Cannot Load This URL in WebView
I want to open glauniversity.in in my webview. 我想在我的Web视图中打开glauniversity.in。 I have implemented following code and searched a lot, but everything seems futile.
我已经实现了以下代码并进行了大量搜索,但一切似乎都没有用。 Any Help will be Appreciated.
任何帮助将不胜感激。 The code goes as follows:
代码如下:
public class WebViews extends Activity {
String link;
WebView webview;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_web_view);
link="glauniversity.in";
webview = findViewById(R.id.wv);
webview.getSettings().setJavaScriptEnabled(true);
webview.setWebViewClient(new WebViewClient(){
@Override
public void onReceivedSslError(WebView view, SslErrorHandler handler, SslError error){
handler.proceed();
}
});
webview.setWebChromeClient(new WebChromeClient() { @Override public boolean onJsAlert(WebView view, String url, String message, JsResult result) { return super.onJsAlert(view, url, message, result); } });
webview.setWebViewClient(new WebViewClient());
webview.loadUrl(link);
}
@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
if (event.getAction() == KeyEvent.ACTION_DOWN) {
switch (keyCode) {
case KeyEvent.KEYCODE_BACK:
if (webview.canGoBack()) {
webview.goBack();
}
else {
finish();
}
return true;
}
}
return super.onKeyDown(keyCode, event);
}
}
glauniversity.in
, This is not a valid url glauniversity.in
,这不是有效的网址
replace this to 替换为
http://glauniversity.in/
Bonus :: 奖励 ::
Check valid url by 检查有效网址
Patterns.WEB_URL.matcher(url).matches()
or 要么
URLUtil.isValidUrl(url)
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