SSH到远程Linux以获取mysql查询命令

Question

I am using ssh key to login to remote Linux server to get result of some commands. This part is working fine. Now I have made a bash script which actually query an DB size of mysql server on that remote linux server. Script is as follows.

#!/bin/bash
# Script to query mysql stats
#set -x
HOST="192.168.0.1"
USER="root"
PASS="PASSSSS"
DB="radius"
CMD=`ssh -p 12345 $HOST mysql -u$HOST -p$PASS --skip-column-names -e "SELECT table_schema "$DB", sum(data_length + index_length)/1024/1024  FROM information_schema.TABLES WHERE table_schema='radius' GROUP BY table_schema;"`
F=`echo $CMD | cut -f1 -d"." | sed 's/[^0-9]*//g'`
echo $F
echo $F

But when I run this script. it gives following error

# ./qmysql.sh
bash: -c: line 0: syntax error near unexpected token `('
bash: -c: line 0: `mysql -u192.168.0.1 -pPASSSS --skip-column-names -e SELECT table_schema radius, sum(data_length + index_length)/1024/1024  FROM information_schema.TABLES WHERE table_schema='radius' GROUP BY table_schema;'

Answer 1

You have some Problems with quotes.

Try something like

... "SELECT table_schema \"$DB\", sum( ...

Answer 2

尝试将`替换为“，并跳过所有引号

 CMD="ssh -p 12345 $HOST mysql -u$HOST -p$PASS --skip-column-names -e \"SELECT table_schema \"$DB\", sum(data_length + index_length)/1024/1024  FROM information_schema.TABLES WHERE table_schema='radius' GROUP BY table_schema;\""