在字符串中的括号之间搜索内容

Question

I want to find text just only inside (), but indexOf return full key value

var str = "some textsome textsome text(texttext)some text"
var arrSplit = str.split(' ')
for(var i = 0; i < arrSplit.length; i++){
    if(arrSplit[i].indexOf('(') >= 0) {
        console.log(arrSplit[i])
    }
}

result

text(texttext)some

I need

(texttext)

Answer 1

To do it only using split() (provided there is only one such pattern in the string):

str.split('(')[1].split(')')[0]

..and using RegEx:

str.match(/\([a-z]*\)/ig)        // returns array containing all matches

Answer 2

Try a regex :

str.match(/\([A-Za-z]*\)/g); // will match all occurrences

You can add more the the part in [] depending on what you need to match. For example, 0-9 if you want to include numbers. Just avoid using .* instead, because this will match something like "(test) nope! (test)" as one block.

Essentially, the gist of this regex is that you want all upper/lower case letters between parenthesis. The parentheses has to be escaped (hence \\( instead of ( ) because parentheses represent grouping in a regex.

Answer 3

Simply try \\(.*?\\) ( RegEx ).

 var str = "some textsome textsome text(texttext)some text" str = str.match(/\\(.*?\\)/); console.log(str[0]); 

OR apply in your implementation:

 var str = "some textsome textsome text(texttext)some text" var arrSplit = str.split(' ') for(var i = 0; i < arrSplit.length; i++){ if(arrSplit[i].indexOf('(') >= 0) { var res = arrSplit[i].match(/\\(.*?\\)/); console.log(res[0]) } }