如何从字典中获取单词列表的值？

Question

(Sorry if I write the post wrong or made some serious mistakes in the code, it is my first week in this)

I have a dictionary, obtained with this code:

import json
sentimientos=open("Sentimientos.txt")
valores={}
for linea in sentimientos:
    termino, valor=linea.split("\t")
    valores[termino]=(int(valor)):
print(valores.items())

That looks like this:

dict_items([('abandon', -2), ('abandoned', -2), ('abandons', -2), ('abducted', -2)...

But with a ton of words

Then I have list of words (obtained from tweets with the method .split(" ")), and I need to check, for each word of the second list, if that words exists on the dictionary, and if so, put his value in the dict.

The code with which I have obtained the words from the list is:

tw = open("salida_tweets.txt")
tweets = []
for linea in tw:
    clean_tweet = json.loads(linea)
    tweets.append(clean_tweet["text"])
    words = [tweet.split(" ") for tweet in tweets]
print(words)

And I have something like:

[['@Brenamae_', 'I', 'WHALE', 'SLAP', 'YOUR', 'FIN', 'AND', 'TELL', 'YOU', 'ONE', 'LAST', 'TIME:'...

But, as before, with a lot of words

As I said, I need to make a list that, for each tweet, print the value of each tweet word that is in the dictionary (the sum of the words if the tweet has more than 1 word).

I'm having serious problems tryng to do that.

¡Thanks everyone!

PD: What I've tried is:

import json
sentimientos=open("Sentimientos.txt")
valores={}
for linea in sentimientos:
    termino, valor=linea.split("\t")
    valores[termino]=(int(valor)):
tw = open("salida_tweets.txt")
tweets = []
for linea in tw:
    clean_tweet = json.loads(linea)
    tweets.append(clean_tweet["text"])
    words = [tweet.split(" ") for tweet in tweets]
    if words in valores:
    valorestweet.append(sum(valores.get(words) for valor in valores)

And what I get is

<ipython-input-68-30a0230d33a7> in <module>()
    19         tweets.append(clean_tweet["text"])
    20         words = [tweet.split(" ") for tweet in tweets] 
    ---> 21         if words in valores:
    22             valorestweet.append(sum(valores.get(words) for valor in valores))
    23 print(valorestweet)

TypeError: unhashable type: 'list'

lines 22 and 23 are remarked in red

Answer 1

I am really not sure I got it right, but let's say you have this input:

tweet0 = "Hello, I am groot"
tweet1 = "My name is red"
tweets = [tweet0, tweet1]

With this dictionnary:

dict = {'Hello': 1, 'I': -2, 'Yellow': -2, 'blue': -5, 'red': 4}

then the expected output would be a list like this one:

[sum of the words value for tweet 1, sum of the world values for tweet 2]

If that is really what you want, then this code does the trick:

dict = {'Hello': 1, 'I': -2, 'Yellow': -2, 'blue': -5, 'red': 4}

tweet0 = "Hello, I am groot"
tweet1 = "My name is red"
tweets = [tweet0, tweet1]

words = [tweet.split(" ") for tweet in tweets]

Results = list()

for i in range(len(tweets)):
    # words[i] are the words from the tweet i
    value = 0
    for word in words[i]:
        if word in dict:
            value += dict[word]
    Results.append(value)

print (Results)

The output with this example is:

[-2, 4]

-2 because only "I" is present in tweet0, and 4 because "red" is present in tweet1.

As you notice, since there is a "," after "Hello", it doesn't take this word into account. This can be fix with an other in statement, and we can also add .lower() method to the str to avoid any problem with the capital letters.

Since I'm not sure about what you want, I just did this proof of concept. I could improve it if you would give us clear examples.