在 Symfony 控制器中调用 KernelInterface

Question

I need to run some Symfony commands from controller in order server are not support ssh connection.

I found this Symfony docs https://symfony.com/doc/3.3/console/command_in_controller.html

/**
 * @Route("/command/run")
 * @Method("POST")
 *
 * @param KernelInterface $kernel
 *
 * @return Response
 * @throws \Exception
 */
public function runCommandAction(KernelInterface $kernel)
{
    $application = new Application($kernel);
    $application->setAutoExit(false);

    $input = new ArrayInput([
        'command' => 'doctrine:schema:update',
        "--force" => true
    ]);

    $output = new BufferedOutput();
    $application->run($input, $output);

    $content = $output->fetch();

    return new Response($content);
}

This code is almost like an example from Symfony docs.

But I get this error when the code is run.

The provided type "Symfony\\Component\\HttpKernel\\KernelInterface" is an interface, and can not be instantiated

Symfony version is 3.3
PHP version is 7.1

I must add that I am using FOSRest bundle, but I guess that should not be a problem.

What I do wrong here? Am I missing something?

Answer 1

I had solved this issue by adding interface in construct class.

/**
 * @var KernelInterface
 */
private $kernel;

public function __construct(KernelInterface $kernel)
{
    $this->kernel = $kernel;
}

/**
 * @Route("/command/run")
 * @Method("POST")
 *
 * @param KernelInterface $kernel
 *
 * @return Response
 * @throws \Exception
 */
public function runCommandAction()
{
    $application = new Application($this->kernel);
    $application->setAutoExit(false);

    $input = new ArrayInput([
        'command' => 'doctrine:schema:update',
        "--force" => true
    ]);

    $output = new BufferedOutput();
    $application->run($input, $output);

    $content = $output->fetch();

    return new Response($content);
}

Answer 2

I think the easiest way to get the kernel in a controller is like this.

$this->get('kernel')

So instead of adding the kernel to the controller object as a private member variable like this.

$application = new Application($this->kernel);

I do this.

$application = new Application($this->get('kernel'));

I'm still running 3.4 at this time.