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类java扩展的Object ArrayList中的Object ArrayList

[英]Object ArrayList within Object ArrayList extended by class java

I have created a class with a group of objects which contain strings and booleans named " Accessories " 我创建了一个包含一组对象的类,这些对象包含名为“ 附件 ”的字符串和布尔值

then created ArrayList class which is then added to the list named " AccessoriesList ", from there more data is inputted. 然后创建ArrayList类,然后将其添加到名为“ AccessoriesList ”的列表中,从那里输入更多数据。

I then created an Accessories object to receive to data from the ArrayList, using a for loop. 然后,我使用for循环创建了一个附件对象,以从ArrayList接收数据。 this still responses as null. 这仍然为null。

I have looked around and found that the most common problem is that the variables have not been initialized. 我环顾四周,发现最常见的问题是变量尚未初始化。 So i tried and still getting the same result 所以我尝试并且仍然得到相同的结果

so here is the accessories class 所以这是配件

    public static class Accessories {

    Accessories(String Accessoriesname, boolean cold, boolean warm, boolean hot, boolean rain, boolean snow, boolean ice, boolean formal, boolean informal) {
    }
    String name =null ; boolean cold; boolean warm; boolean hot; boolean rain; boolean snow; boolean ice; boolean formal; boolean informal;
}

Here is the AccessoriesList class 这是AccessoriesList

 public ArrayList createAccessories() {
    ArrayList<Accessories> Accessoriesist = new ArrayList<Accessories>();
    Accessoriesist.add(new Accessories("Bag", true, true, true, false, false, false, true, true));
    Accessoriesist.add(new Accessories("Gloves", true, false, false, true, true, true, true, true));
    Accessoriesist.add(new Accessories("Hat", true, false, false, true, true, true, false, true));
    Accessoriesist.add(new Accessories("Poncho", false, true, true, false, false, false, false, true));
    Accessoriesist.add(new Accessories("Scarf", true, true, false, true, true, true, true, true));
    Accessoriesist.add(new Accessories("Sunglasses", false, true, true, false, false, false, true, true));
    Accessoriesist.add(new Accessories("Tie", true, true, true, true, true, true, true, true));

    Accessories getAccessories =null;
    String getname = null;
    for (int i = 0; i < Accessoriesist.size(); i++) {
        getAccessories =  Accessoriesist.get(i);
        getname = getAccessories.name;
        System.out.println("this is the name : " + getname);
        System.out.println("this is the Accessoriesist : " + Accessoriesist.get(i));
    }
    return Accessoriesist;
}

Instead of receiving the information, I receive the hash-code. 我没有收到信息,而是收到哈希码。

I am trying to throw an Accessories Object(orginal) from an ArrayList, into another Accessories Object(new). 我试图将一个ArrayList中的附件对象(原始)放入另一个附件对象(新)中。 i am trying to pull the data from the Accessories Object(new) 我试图从附件对象(新)中提取数据

You have two problems: 您有两个问题:

First, your constructor never copies the properties you pass to it into the class: Accessories(String Accessoriesname, boolean cold, boolean warm, boolean hot, boolean rain, boolean snow, boolean ice, boolean formal, boolean informal) { } 首先,构造函数永远不要将传递给它的属性复制到该类中:附件(字符串附件名称,布尔冷,布尔温暖,布尔热,布尔雨,布尔雪,布尔冰,布尔正式,布尔非正式){}

Think of a constructor as a method call with variable parameters: in this case you do nothing between your curly braces { and } . 将构造函数视为带有可变参数的方法调用:在这种情况下,您在花括号{}之间不执行任何操作。 Java provides you with the this keyword to refer to a property of the class instance. Java为您提供了this关键字来引用类实例的属性。 So you need to explicitly copy the parameters passed to your constructor to the properties of your class instance: 因此,您需要将传递给构造函数的参数显式复制到类实例的属性中:

Accessories(String Accessories name, boolean cold, boolean warm, boolean hot, boolean rain, boolean snow, boolean ice, boolean formal, boolean informal) {
    this.name = name
    this.cold = cold
    this.warm = warm
    this.hot = hot
    this.rain = rain
    this.snow = snow
    this.ice = ice
    this.formal = formal
    this.informal = informal
}

Second, because this line of code is concatenating a String with an object, it will call the .toString() method on your Accessories object: 其次,由于此行代码将一个String与一个对象串联在一起,因此它将在您的Accessories对象上调用.toString()方法:

    System.out.println("this is the Accessoriesist : " + Accessoriesist.get(i));

The default implementation of the .toString() method is inherited from the Object superclass. .toString()方法的默认实现是从Object超类继承的。 If you'd like to override it, just add a method to your class with the same method signature as Object.toString() 如果您想重写它,只需将一个方法添加到您的类中,该方法具有与Object.toString()相同的方法签名

public String toString() {
    StringBuilder sb = new StringBuilder(this.name);
    if (ice) {
        sb.append(" (ice)")
    }
    // other properties
    return sb.toString()
}

A few final notes: 最后几点注意事项:

  • It is conventional in Java to use CamelCase. Java中通常使用CamelCase。 For classes, we use a capital letter for the first letter (MyClass) and for class member variables and parameters we use a lowercase letter for the first letter (myClass). 对于类,我们将大写字母用作首字母(MyClass),对于类成员变量和参数,将小写字母用作首字母(myClass)。 So your ArrayList<Accessories> Accessoriesist would be ArrayList<Accessories> accessoriesList following this convention. 因此,遵循此约定,您的ArrayList<Accessories> Accessoriesist将是ArrayList<Accessories> accessoriesList
  • It might be a good idea to make all of your different properties (cold, warm, ice, snow, etc) an enum called something like Properties and to have your Accessories class contain a List. 最好将所有不同的属性(冷,暖,冰,雪等)设为一个称为“ Propertiesenum并让您的Accessories类包含一个List。

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