[英]How can I sort a Java list using two different values?
public void sortLeagueTable(List<LeagueTableItem> table) {
Collections.sort(table, new Comparator<LeagueTableItem>(){
public int compare(LeagueTableItem o1, LeagueTableItem o2){
return o2.getPoints() - o1.getPoints();
}
});
}
This code sorts two lists based on the value of the object called points. 此代码根据名为points的对象的值对两个列表进行排序。 After I sort it based on the value point
I want to sort it again based on the value goalScored
. 在我根据值point
进行排序后,我想根据值goalScored
再次对其进行排序。 So, if the points of two teams are equal, I want to sort it again based on the goalScored
value. 所以,如果两支球队的分数相等,我想根据goalScored
值再次对其进行排序。
How can I do that? 我怎样才能做到这一点?
Java 8's enhancements to the Comparator
interface give you a pretty elegant way of achieving this: Java 8对Comparator
界面的增强为您提供了一种非常优雅的方法来实现这一目标:
table.sort(Comparator.comparingInt(LeagueTableItem::getPoints)
.thenComparingInt(LeagueTableItem::goalScored));
Just add another condition to your comparator: 只需在比较器中添加另一个条件:
public int compare(LeagueTableItem o1, LeagueTableItem o2){
int diff = o2.getPoints() - o1.getPoints();
if (diff == 0) {
diff = o2.goalScored() - o1.goalScored();
}
return diff;
}
public int compare(LeagueTableItem o1, LeagueTableItem o2) {
if (o2.getPoints() == o1.getPoints()) {
return o2.goalsScored() - o1.goalsScored();
} else {
return o2.getPoints() - o1.getPoints();
}
}
First it gets the o1 and o2's points and compare them. 首先,它获得o1和o2的点并进行比较。 If they are equal, the if statement proceed to calculate which o has more goals scored and returns the result, else if the points are NOT equal it returns the result. 如果它们相等,则if语句继续计算哪个o有更多的目标得分并返回结果,否则如果点不相等则返回结果。
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