[英]Use exec to execute a file inside a function with globals()
I need to execute a file inside a python shell. 我需要在python shell中执行文件。
I can 我可以
exec(open('Test.py').read())
But I need to call it from inside a function. 但是我需要从函数内部调用它。
"Test.py" will set variable C=10 “ Test.py”将设置变量C = 10
So, 所以,
#x.py
def load(file):
exec(open(file).read(),globals())
>>> import x
>>> x.load('Test.py')
>>> C
>>> NameError: name 'C' is not defined
I have passed in the globals, but I still cant access the varibales from exec. 我已经通过了全局变量,但是我仍然无法从exec访问变量。 References:
参考文献:
In Python, why doesn't an import in an exec in a function work? 在Python中,为什么在函数中的exec中导入不起作用?
How to execute a file within the python interpreter? 如何在python解释器中执行文件?
use import
instead 改用
import
from Test import C
print C
EDIT: 编辑:
If Test.py is in a different directory, you have to modify the sys.path
如果Test.py位于其他目录中,则必须修改
sys.path
import sys.path
sys.path.insert(0, "path_to_directory")
from Test import C
print C
So here is one way to do it 所以这是一种方法
#x.py
def load(file):
exec(open(file).read())
return locals()
>>> import x
>>> var = x.load('Test.py')
>>> locals().update(var)
>>> C
>>> 10
Hope it helps 希望能帮助到你
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