“ For循环”以升序排列数字。 [ERROR]指针和整数比较

Question

This is a very simple program, to arrange numbers in ascending order. Now here I don't know how it says there is the comparison between integer and pointer, in all the for loops. I am a noob by the way.

#include <stdio.h>

int main()
{

    int number[100],total,i,j,temp;;

    printf("Enter the quantity of the numbers you want \n");
    scanf("%d",&total);

    printf("Enter the numbers \n");
    for(i=0; i<total; i++){

        scanf("%d",&number[i]);
    }

    for(i=0; i < (number-1); i++){ 

        for(j=(i+1); j  < number; j++){  

            if(number[i]>number[j]){
                temp = number[i];
                number[i] = number[j];
                number[j] = temp;
           }

        }

    }
    for(i=0; i < number; i++){  

        printf("%d \n", number[i]);
    }



    return 0;
}

Answer 1

You are using i < number where i is int and number is an array

Just change those lines to below

for(i=0; i < (total-1); i++){ 

        for(j=(i+1); j  < total; j++){  


for(i=0; i < total; i++){ 

Answer 2

the following proposed code:

1. properly checks for errors
2. properly outputs error messages to stderr
3. properly minimizes the scope of variables
4. cleanly compiles
5. incorporates appropriate horizontal spacing after commas, after semicolons, inside parens, around C operators
6. performs the desired functionality
7. makes use of a VLA (variable length array) so the number of numbers could be most any positive number
8. separates code blocks (for, if, else, while, do...while, switch, case, default) via a single blank line
9. does not contain random blank lines
10. documents why each header file is included
11. does not allow the user to enter a negative count for the number of numbers
12. follows the axiom: only one statement per line and (at most) one variable declaration per statement.

And now, the proposed code:

#include <stdio.h>   // scanf(), perror(), printf()
#include <stdlib.h>  // exit(), EXIT_FAILURE

int main( void )
{
    int total;

    printf("Enter the quantity of the numbers you want \n");
    if( 1 != scanf( "%d", &total ) )
    {
        perror( "scanf for count of numbers failed" );
        exit( EXIT_FAILURE );
    }

    // implied else, scanf successful

    if( !total )
    {  // then 0 entered
        printf( "Exiting, no numbers to enter\n" );
        return 0;
    }

    // implied else, some numbers to enter

    int number[ total ];   // << uses the VLA feature of C

    for( unsigned i = 0; i < total; i++ )
    {
        printf( "Enter number %u: ", i+1 );

        if( 1 != scanf( "%d", &number[i] ) )
        {
            perror( "scanf for a number failed" );
            exit( EXIT_FAILURE );
        }

        // implied else, scanf successful
    }

    for( int i = 0; i < (total - 1); i++ )
    {
        for( int j = (i+1); j < total; j++ )
        {
            if( number[i] > number[j] )
            {
                int temp  = number[i];
                number[i] = number[j];
                number[j] = temp;
            }
        }
    }

    for( unsigned i = 0; i < total; i++ )
    {
        printf("%d \n", number[i]);
    }

    return 0;
} // end function: main