Qt Creator：在调试和发布模式下类模板的不同行为

Question

I'm trying to specialize template member function. The problem is that in Debug mode calls specialization of method, but in Release calls non-specialized function.

For example, I have class template and specialized method

template <typename T>
class SimpleClass
{
public:
    void doSomething(const T& arg)
    {
        std::cout << "doSomething(const T& arg)" << std::endl;
    }
};
template <>
void SimpleClass<double>::doSomething(const double& arg)
{
    std::cout << "doSomething(const double& arg)" << std::endl;
}

int main(int argc, char **argv)
{
    SimpleClass<double> obj;
    obj.doSomething(1);
    return 0;
}

I'm expecting, that output will "doSomething(const double& arg)" .

So in Debug mode I got it, but in Release I got this: "doSomething(const T& arg)"

My question is why that code behave this way and how can I fix it? Just in case, my .pro file

TEMPLATE = app
CONFIG += console c++11
CONFIG -= app_bundle
SOURCES += main.cpp \
    mathop.cpp
HEADERS += \
    mathop.h

edit: I'm using Qt 5.9.1

edit: forgot #include <iostream> before using cout

Answer 1

As you're calling doSomething() with an integer as parameter, I guess the compiler is just trying to find an arbitrary match here. I can't say why debug and release builds behave differently, but I would expect it to work as expected when explicitely using a float value in the call:

obj.doSomething(1.0);