正则表达式仅接受0,1，（,,, |，&&

Question

I am trying to create a regular expression that contains only below 6 characters in a string

0,1,(,),|,&

I came up with this regular expression

^[0-1\\|()\\&]$

But it seems to fail even when valid string is given as input. As below

const inputStr = "(0&(1&(1|0))";
const validateStr = new RegExp("^[0-1\|\(\)\&]$");
const isValid = validateStr.test(inputStr);

Above need to be returned true, but the output of isValid is false. Please let me know where I am doing wrong.

Answer 1

You need to add a plus after your character set to search the whole string!

 const inputStr = "(0&(1&(1|0))"; const validateStr = new RegExp(/^[0-1()|&]+$/); const isValid = validateStr.test(inputStr); console.log(isValid);