一种视图中差异文件的路径-Joomla

Question

I'm trying to put a link in a component's view file (default.php) to another file in the same view (default_formulaire.php) as you can see below:

But I really don't know how to access it in PHP. I know that the default.php file's url is:
index.php?option=com_multicontact&view=reclamation but I don't know that of default_formulaire.php .

Thanks for any help :)

Answer 1

如果您需要在joomla中访问其他布局，则需要在joomla url中添加一个布局值，例如index.php?option=com_multicontact&view=reclamation&layout=default_formulaire

Answer 2

The link to any view in Joomla is the following:

index.php?option=com_componentname&view=viewname&layout=layoutname

However, if the layout is omitted from the URL, then it is assumed that it is set to default . So, the following URL:

index.php?option=com_componentname&view=viewname

Will mean that the layout is default , which means that the default.php file will be loaded.

So, in your situation, the URL to load the default_formulaire layout will be:

index.php?option=com_multicontact&view=reclamation&view=default_formulaire