如何在TypeScript中将导入添加到默认导出

Question

I have this TypeScript node module that imports some base errors ( errors1 and errors2 ) and define some module specific errors3 :

// in errors3.ts
import errors1 from './errors1'
import errors2 from './errors2'

const errors3 = {
  ...
}

export default ? // <-- want to merge and export all errors here

Is there a way to combine all 3 error objects into one default export without explicit merging these objects into one manually (ie via Object.assign , lodash , etc?

Answer 1

You can use a barrel to export them all and then import them under a namespace.

https://basarat.gitbooks.io/typescript/docs/tips/barrel.html