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Haskell:否定Ordering类型的值

[英]Haskell: negate a value of type Ordering

Is there a way to negate or invert a value of type Ordering? 有没有一种方法可以否定或求逆Ordering类型的值? Something like this: 像这样:

inv = not compare

If you are getting the Ordering from compare , then you can change it to flip compare : 如果要从compare获得Ordering,则可以将其更改为flip compare

> flip compare 3 4
GT

Or you can wrap the values in Down from Data.Ord , a newtype that exists to reverse the ordering of things: 或者,您可以将值包装在Data.Ord DownData.Ord是一种新的类型,可以用来颠倒事物的顺序:

> compare (Down 3) (Down 4)
GT

If you can't or don't want to change the place that the Ordering comes from, you'll need a function to invert it and I don't know of a built-in one. 如果您不能或不想更改Ordering的来源,则需要一个函数将其反转,并且我不知道内置函数。 You can write the obvious pattern match, or since Ordering is itself ordered: 您可以编写明显的模式匹配,或者由于Ordering本身是有序的:

inv :: Ordering -> Ordering
inv = compare EQ

Yes it is contained in Data.Ord and is a type called Down . 是的,它包含在Data.Ord中,并且是一个名为Down的类型。

I cite: 我引用:

"If a has an Ord instance associated with it then comparing two values thus wrapped will give you the opposite of their normal sort order." “如果一个具有与之关联的Ord实例,则比较由此包装的两个值将得到与它们正常排序顺序相反的结果。”

Reference: https://hackage.haskell.org/package/base-4.10.1.0/docs/Data-Ord.html 参考: https : //hackage.haskell.org/package/base-4.10.1.0/docs/Data-Ord.html

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