用空格或逗号分隔的多个单词的正则表达式

Question

I'm trying to create regex for multiple strings separated by comma or space.

Lorem Ipsum // valid
Lorem, Ipsum //valid
Lorem, Ipsum, Ipsum, Ipsum // multiple valid
Lorem // invalid without space/comma

Here is what i have so far:

^\w+(,\s*\w+){3}$/

Answer 1

You may use

^\w+(?:(?:,\s\w+)+|(?:\s\w+)+)$

See the regex demo .

The regex matches:

• ^ - start of string
• \\w+ - 1+ word chars
• (?: - start of an alternation group:
  • (?:,\\s\\w+)+ - , , whitespace, 1+ word chars
  • | - or
  • (?:\\s\\w+)+ - whitespace and then 1+ word chars
• ) - end of group
• $ - end of string.

You may shorten the pattern using a lookahead and a capturing group:

^\w+(?=(,?\s))(?:\1\w+)+$

See the regex demo . Here, the difference is (?=(,?\\s))(?:\\1\\w+)+ :

• (?=(,?\\s)) - a positive lookahead that checks if there is an optional , and then a whitespace immediately to the right of the current location and captures that sequence into Group 1
• (?:\\1\\w+)+ - 1 or more sequences of:
  • \\1 - the same text captured into Group 1
  • \\w+ - 1+ word chars.

See the regex demo .

Answer 2

Assuming that you want to match the whole phrase:

^(\w+(,|\s)\s*)+\w+$

should do the trick.

Answer 3

试试这个正则表达式：

^(\w+[, ]+)*\w+$

Answer 4

由于以上都不适合我，我想出了这个：

/([^,\s]+)/g