如何将JSON响应转换为Java列表-使用Rest Assure确保进行API测试

Question

I have a nested JSON response. JsonResponse Screenshot

I want to get the the dictionary at 0th location from the list and then get a particular element from it. For eg In response, {0} and {1}, I want to get complete {0} as a result. Then from {0}, I want to extract "Id" value only.
I don't want to use the JsonPath.read(JsonResponse String, JSON Path) everytime. So looking for some simple and better alternative.

How to convert JSON response to Java List. Below is the response.

Response resp = given().header("Authorization", "Bearer "+"dwded").
                accept(ContentType.JSON).
                when().
                get("https://example.com");      
                return resp;

Answer 1

For testing a web-API or REST endpoint, I would recommend Karate .

So it becomes simple:

* def id = response[0].Id

Answer 2

In the swagger editor pet example.

  responses:
    200:
      description: "successful operation"
      schema:
        type: "array"
        items:
          $ref: "#/definitions/Pet"

A model is generated from the

  Pet:
    type: "object"
    properties:
      name:
        type: "string"
        example: "doggie"

This generated a java class

public class Pet   {

  @JsonProperty("name")
  private String name = null;

The api shows a REST that returns an entity that can be shown as an array of json objects

    ResponseEntity<List<Pet>> findPetsByStatus( @NotNull@ApiParam(value = "Status values that need to be considered for filter", required = true, allowableValues = "available, pending, sold") @RequestParam(value = "status", required = true) List<String> status);