[英]Converting group() to float or int format
This is a followup to Python. 这是Python的后续版本。 How to print a certain part of a line after it had been "re.searched" from a file 从文件“重新搜索”后如何打印一行的特定部分
Here is the initial code, based on the accepted answer to the linked question: 这是初始代码,基于链接问题的公认答案:
import re
VSP = input("Номер ВСП (четыре цифры): ")
c = re.compile('(\d+\.226\.\S+)\s+\S+' + VSP)
Tunnel0_IP_VSP = re.search(c, open('OUS_IP.txt').read())
print (Tunnel1_IP_VSP.group(1))
Номер ВСП (четыре цифры): 1020
10.226.27.60
I was able to find the requested IP address in text file. 我能够在文本文件中找到请求的IP地址。
My goal is to somehow convert the string "10.226.27.60"
to a format that would allow me to use it in mathematical formulas. 我的目标是以某种方式将字符串"10.226.27.60"
转换为允许我在数学公式中使用的格式。 For example, I want to get another address "10.226.27.59"
by subtracting 1 from the last octet of the original address. 例如,我想通过从原始地址的最后一个八位位组减去1得到另一个地址"10.226.27.59"
。
You can use the ipaddress
module for Python 3: 您可以将ipaddress
模块用于Python 3:
>>> import ipaddress
>>> ip = ipaddress.IPv4Address('10.226.27.60')
>>> ip - 1
IPv4Address('10.226.27.59')
The IPv4Address
class allows for arithmetic operators IPv4Address
类允许算术运算符
Docs: https://docs.python.org/3/library/ipaddress.html#operators 文件: https : //docs.python.org/3/library/ipaddress.html#operators
You could take the string
(what you end up with): 您可以使用string
(最终得到的结果):
s = "10.226.27.60"
and then split
on '.'
然后在'.'
上split
and use a list-comprehension
to convert the parts to integers
: 并使用list-comprehension
将零件转换为integers
:
p = [int(i) for i in s.split('.')]
and then finally, subtract 1
from the last element: 最后,从最后一个元素中减去1
:
p[-1] -= 1
to get p
as: 得到p
为:
[10, 226, 27, 59]
Note that if you want to display this list in the original string
format, then you can use join
with a generator-expression
: 请注意,如果要以原始string
格式显示此列表,则可以将join
与generator-expression
:
".".join(str(i) for i in p)
#"10.226.27.60"
You can do: 你可以做:
string = "10.226.27.60".split(".")
number_list = [int(number) for number in string]
print(number_list)
[10, 226, 27, 60] you can calculate each element [10,226,27,60]您可以计算每个元素
convert back: 转换回:
string_again = ".".join(str(number) for number in number_list)
print(string_again)
10.226.27.60 10.226.27.60
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