从Firebase函数中的异步函数返回什么？

Question

Inside the async function, do I need to return await for the function to complete correctly, or is the code below fine?

const db = admin.firestore();

export const onUserCreate = functions.auth.user().onCreate(async event => {
    try {
        const user: User = {
            userId: event.data.uid,
            email: event.data.email
        };

        await db.doc(`users/${user.userId}`).set(user, {merge: true});
    } catch (error) {
        throw error;
    }
});

Answer 1

This function already returns a promise that only resolves after your db.doc(...).set(..) has itself resolved. return await would in this case be redundant.

So I think your code is fine as is, but it's simple enough that there is the possible improvement of forgetting about using async/await entirely, and just returning the promise directly. Eg: return db.doc(...).set(...) , without declaring the function as async.