根据列表php提取选定的数组值

Question

I have a list of array keys in form of a string

"hasAddStrict,freqItems,freqAmount,freqUnit,freqFirstDayOfWeek"

Now, want to extract only those values, ie $myarray['hasAddstrict'] should become $hasAddStrict, etc.

Is there a short way to do it? My rather dirty solution:

$ff = explode(',' ,"hasAddStrict,freqItems,freqAmount,freqUnit,freqFirstDayOfWeek");
    foreach ( $ff   as $key){   $ff[$key] =    $SERVICE[$key]  ;    }
    extract($ff);

Answer 1

I agree with Jeff that there isn't really a better way, and that keeping the variables as an array is probably a better idea, but you could wrap it up in a function for convenience (tested in php 5.6):

<?php

function array_extract(array $assoc_array, $keys_list)
{
    return array_intersect_key($assoc_array, array_flip(explode(',', $keys_list)));
}

extract(array_extract($SERVICE, "hasAddStrict,freqItems,freqAmount,freqUnit,freqFirstDayOfWeek"));

When tested as follows:

$SERVICE = [
    'hasAddStrict' => 123,
    'freqItems' => 456,
    'freqAmount' => 789,
    'freqUnit' => 'abc',
    'freqFirstDayOfWeek' => 'def',
];

extract(array_extract($SERVICE, "hasAddStrict,freqItems,freqAmount,freqUnit,freqFirstDayOfWeek"));

var_dump($hasAddStrict, $freqItems, $freqAmount, $freqUnit, $freqFirstDayOfWeek);

You get output:

int(123)
int(456)
int(789)
string(3) "abc"
string(3) "def"