我正在尝试使数组在 c 中打印出来

Question

#include <stdio.h>

int table [100];

int main (void)
{
    for (int i=0; i<100; i++)
    {
        i = table [i];
        printf("%i\n", table[i]);
    }
}

I'm trying to make an array that stores 0 to table[0], 1 to table [1] and so forth and then prints it's own value.

Right now the code outputs 0's.

Answer 1

您的分配倒退了 - 您需要将i分配给table[i] ，而不是像您目前拥有的相反：

table[i] = i;

Answer 2

#include <stdio.h>

int table [100];

int main (void)
{
    for (int i=0; i<100; i++)
    {
        table [i] = i;
        printf("%i\n", i);
    }
}

There you go. With nothing in the array and the iterator being reset every loop, it won't even print all hundred zeroes, just 0#0 and 0#1 forever. Now. Alternatively...

#include <stdio.h>

int table [] = {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,
    21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,
    41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,
    61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,
    81,82,83,84,85,86,87,88,89,90,91,92,93,94,95,96,97,98,99};

int main (void)
{
    for (int i=0; i<100; i++)
    {
        printf("%i\n", table[i]);
    }
}