Powershell正则表达式替换

Question

Team,

I have a file in Windows where the content is like the below:

460 ls

461 cd ..

462 ls

463 cd ubuntu/

464 ls

465 cd test/

466 ls

467 cd ..

468 openvpn

I want to remove all the numbers which are present in the beginning and get the actual content.

I have tried :

$var= Get-Content C:\Scripts\test.txt
$var.replace("/[4 6]/","");

$var.replace("/[4 6]/","");

($var.replace("4","")).Replace("6","")

But is it possible to get some regular expression solution for this.

Answer 1

When processing a file line by line you may use the following pattern:

$var -replace '^[\s\d]+'

See the regex demo

When processing a whole file as one string you would need to use

$var -replace '(?m)^[\p{Zs}\t\d]+'

in order not to overflow across lines. See a .NET regex demo .

Details

• ^ - start of the input (when (?m) is used at the start of the pattern, ^ matches start of input and start of each line)
• [\\s\\d]+ - one or more whitespaces ( \\s ) or digits ( \\d )
• [\\p{Zs}\\t] - matches any horizontal whitespace.

Answer 2

You can do so by using the following regular expression.

$result = $var -replace '^[\s]?\d+'

To update the file with the $result you can use the code below.

Set-Content -Value $result -Path C:\Scripts\test.txt