[英]How to convert every other row to column in T-SQL?
Perhaps this was a question that has already been asked. 也许这是一个已被问过的问题。 How should one convert every other row to columns in T-SQL? 如何将每隔一行转换为T-SQL中的列? Here is some T-sql to create the table and sample data. 这里有一些T-sql来创建表和示例数据。
CREATE TABLE Names
(
[ID] int,
HouseholdId int,
[FullName] varchar(max),
[ssn] varchar(max),
isPrimary bit
)
;
INSERT INTO names(ID, HouseholdId, [FullName], ssn, isPrimary)
VALUES
(1, 10,'User1', '111111111', 1),
(2, 10, 'User2', '222222222', 0),
(3, 10, 'User3', '333333333', 0),
(4, 10, 'User4', '444444444', 0),
(5, 10,'User5', '555555555', 0),
(6, 20, 'User6', '666666666', 1),
(7, 20, 'User7', '777777777', 0)
;
I would like to convert every household's users into two columns, something like this. 我想将每个家庭的用户转换成两列,就像这样。
HouseHold User Name 1 SSN 1 User Name 2 SSN 2
10 User1 111111111 User2 222222222
User3 333333333 User4 444444444
User5 555555555
20 User6 666666666 User7 777777777
how would I do this? 我该怎么做?
here is the sql that will do what you are looking for. 这是sql将执行您正在寻找的。 It assigns a row number by partitioning within household id. 它通过在家庭ID内分区来分配行号。 Then uses a self join to lay out side-by-side. 然后使用自联接并排布局。 http://sqlfiddle.com/#!6/c8933/10/0 http://sqlfiddle.com/#!6/c8933/10/0
WITH T AS (
select HouseholdId, ID, Fullname, ssn
, ROW_NUMBER() OVER(PARTITION BY HouseHoldId Order by ID) AS RNUM
FROM Names
)
SELECT A.HouseholdId, A.fullname as username1, A.SSN as ssn1
, B.fullname as username2, B.ssn as ssn2
FROM T A
LEFT JOIN T B ON A.householdID = B.HouseholdId
AND (A.RNUM = B.RNUM - 1)
WHERE A.RNUM % 2 = 1
This is how you could accomplish the same using a pivot
. 这是使用pivot
完成相同操作的方法。
select b.HouseholdID
, b.[User Name 1]
, b.[SSN 1]
, b.[User Name 2]
, b.[SSN 2]
from (
select sub.HouseholdId
, sub.col_nm_prelim + cast( (((sub.row_nbr + 1) % 2) + 1) as char(1)) as col_nm
, ceiling(sub.row_nbr / 2.0) as row_nbr
, sub.col_val
from (
select n.HouseholdId
, 'User Name ' as col_nm_prelim
, row_number() over (partition by n.HouseHoldID order by n.ID asc) as row_nbr
, n.FullName as col_val
from Names as n
union all
select n.HouseholdId
, 'SSN ' as col_nm_prelim
, row_number() over (partition by n.HouseHoldID order by n.ID asc) as row_nbr
, n.SSN as col_val
from Names as n
) as sub
) as a
pivot (max(a.col_val) for a.col_nm in ([User Name 1], [User Name 2], [SSN 1], [SSN 2])) as b
order by b.HouseholdID asc
, b.row_nbr asc
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