如何引发异常并继续执行 Python 中的主要代码

Question

Given the following simple example:

while True:

    readme = input("Write here something:")

    if readme == "":

        raise Exception("That was empty!")

(1) How can the main code / loop continue to work after an Exception has been thrown? (2) And if we simultaneously run another thread, how can we catch the Exception in there?

Edit: is it possible to do this without having a try/except block inside the loop?

Answer 1

Yes it is possible with try/except.

Try making a function like so:

from inspect import currentframe,getframeinfo
def Raise(ex):

    cf = currentframe()
    #Get the line
    line=cf.f_back.f_lineno
    print('Traceback:\n'+ex+'\nin line '+str(line))
    wait=input('Press Enter to continue excecution.')

And then call:

myexception('That was empty!)

For example (from the example):

from inspect import currentframe,getframeinfo

    def Raise(ex):
    cf = currentframe()
    #Get the line
    line=cf.f_back.f_lineno
    print('Traceback:\n'+ex+'\nin line '+str(line))
    wait=input('Press Enter to continue excecution.')

readme = input("Write here something:")
if readme == "":
    Raise("That was empty!")

Answer 2

Without using the try/catch it is not possible in python. When we call a function in python and it raises a exception, the exceptions is propagated to the caller function and it continues.

If you do not handle the the exception anywhere in the above chain, interpreter just throw it out to the user.