根据条件从数据框中删除行

Question

I know this has to have been addressed before, but I cannot seem to find an answer that works

I have the columns that I want to test the condition against and I want to remove all rows where their value in any of the three columns is above a given value.

x  a  b  c  d  
1  2  1  3  4  
2  3  5  2  2  
3  3  3  3  2  
4  1  2  3  3  

if I ran against this dataframe, with my cutoff value being anything greater than 3, then I should be returned with

x  a  b  c  d
3  3  3  3  2
4  1  2  3  3

Answer 1

如果您的数据帧为df则为df df[~df[df>3].any(axis=1)]

Answer 2

You can remove rows like:

import pandas as pd
import numpy as np

df.loc[df.x>=3,:]

You can also use conditions using numpy logical_and and logical_or if you have upper and lower limit

df = df.loc[np.logical_and(dd.x<=3,df.x<=0),:] 

You can also use ~

df.loc[~df.x.isin([1,2]),:] 

Answer 3

Something like this should work.

cols = ["a" , "b" , "c"]
greater_than_3 = (df[cols]>3).any(axis=1)
df = df[!greater_than_3]