在Typescript中声明Ramda组合/管道函数的类型

Question

I'm currently trying to use Ramda with Typescript, but i can't find any examples about declaring types for functions expressions created by pipe (or compose) function, below is my code:

interface VersionObject {
    major: number;
    minor: number;
    patch: number;
}

const parseVersionString = pipe(
    split('.'),
    map(unless(isNaN, parseInt)), // btw, ts complain about this parseInt
    zip(['major', 'minor', 'patch']),
    fromPairs
);

What i'm trying to do is to declare that parseVersionString receives an string and returns a VersionObject , how could i do that?

Answer 1

Two syntax variants which are equivalent:

const parseVersionString: (s: string) => VersionObject = pipe(

const parseVersionString: { (s: string): VersionObject } = pipe(