Findall与字符串groovy数组

Question

I have a string /sample/data . When I split using split I get the following result,

["","sample","data"]

I want to ignore the empty string(s). So I tried the following code,

"/sample/data".split('/').findAll(it != "")

It gives me an error " cannot call String[] findAll with argument bool ".

How can I split and get a List without empty string in it?

Answer 1

split method returns array. If you need List, use tokenize

"/sample/data".tokenize('/')

also you don't need to use findAll in this case.

Answer 2

You can do as below:

println "/sample/data".split('/').findAll {it}

findAll {it} would fetch all the non empty values.

Answer 3

Parens would work (see comments on question). So your solution is already close:

"/a/b".split("/").findAll()

Because most of the Groovy functions have a zero arity, which will call the function with an identity closure. And since an empty string is considered falsey, this will filter them out.