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用mySQL中的其他表选择结果更新表中的字段

[英]Update field in table with result of select from other table in mySQL

I have a follow-up question to sum of counts of different columns of same table I want to update a field (Z) in another table (B), which also has 'ID' with the results (A.COUNT_TOTAL) of the select query: 我有一个后续问题要汇总同一张表的不同列的计数,我想更新另一个表(B)中的字段(Z),该表的选择结果(A.COUNT_TOTAL)也带有“ ID”查询:

SELECT A.ID, SUM(A.COUNTS) AS COUNT_TOTAL
FROM
(
SELECT X AS ID, COUNT(*) AS COUNTS FROM TABLE1 GROUP BY X
UNION ALL
SELECT Y AS ID, COUNT(*) AS COUNTS FROM TABLE1 GROUP BY Y
) A
GROUP BY A.ID
ORDER BY A.ID;`

I tried following statement, (but get a vague error message): 我尝试了以下语句,(但收到模糊的错误消息):

 UPDATE B
    INNER JOIN (
    SELECT A.ID, SUM(A.COUNTS) AS COUNT_TOTAL
    FROM
    (
    SELECT X AS ID, COUNT(*) AS COUNTS FROM TABLE1 GROUP BY X
    UNION ALL
    SELECT Y AS ID, COUNT(*) AS COUNTS FROM TABLE1 GROUP BY Y
    ) A
    GROUP BY A.ID) as A on B.ID = A.ID
    SET B.Z = A.COUNT_TOTAL

You have ambiguos (and wrong reference to alias A .. you are using two times the same name for different alias ) Try using a differnent alias for different subquery eg: 您有歧义(并且对别名A ..的引用错误,您对不同的别名使用了两次相同的名称)尝试对不同的子查询使用不同的别名,例如:

  UPDATE B
  INNER JOIN (
  SELECT A.ID, SUM(A.COUNTS) AS COUNT_TOTAL
  FROM
  (
  SELECT X AS ID, COUNT(*) AS COUNTS FROM TABLE1 GROUP BY X
  UNION ALL
  SELECT Y AS ID, COUNT(*) AS COUNTS FROM TABLE1 GROUP BY Y
  ) A
  GROUP BY A.ID)  T on B.ID = T.ID
  SET B.Z = T.COUNT_TOTAL

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